The Split, Abelian Kernel,
Case of the Regular Inverse Galois Problem
This file is an addendum to RIGP.html.
When
an extension splits, and has abelian kernel, some elements of the
regular inverse Galois problem seem easy.
Using [FrJ, §16.4]2, we comment on when this is
encouraging – as a
guide for the Nielsen-RIGP conjecture – and, equally, when it is
misleading – because
it doesn't hint at problems in extending explicit realizations to where
the kernel is nilpotent,
or with the non-split case.
I. NOTATION FOR
SEMI-DIRECT AND
WREATH PRODUCTS:
Consider this short exact
sequence of groups, which we assume is split:
Basic Sequence: 1 →Ker →G→G*→1.
That is, you can represent G
as 2x2 matrices of the form:
|g* 0
|
| a
1 |, with g*∈G*
and a ∈Ker
and where matrix multiplication gives
the multiplication in G.
If
we call the matrix above M(
g*, a) and we multiply
it by M( h*, b), then the result
is what you
would expect from matrix multiplication:
M(g*h*, (a)h*+b), as if h* is a matrix
acting on the right of a.
We write G
as Ker×s G*
– the semi-direct
product of Ker and G*.
If instead you
wanted a left action of G*
on Ker, you could put a in the upper
right corner, and 0
in the lower left. (I've written the second slot with a "+" as if Ker
is abelian. That, however, is unnecessary; we could write that instead
as (a)h*. b.)
The former case is that of [FrJ, p. 251]2,
though it
is common to see the other. The notation with G*
on the right
makes transparent our homomorphism G→G*.
Now suppose T: G*→Sn
is a degree n
permutation
representation of G*.
Let M be
any group
whatsoever. Then, a natural case of semi-direct product takes Ker
= Mn,
the direct
product of M,
n times.
The action of an
element g*∈G*
is just to permute
the slots of Ker
according
to the permutation that g* represents. The resulting semi-direct
product is called the wreath
product.
Compatible with
[FrJ, p. 252]2 we could denote it M
wrT G*.
II. REALIZING WREATH
PRODUCTS
REGULARLY:
Assume we have regular realizations of G*and
M. Then,
[FrJ, Lem. 13.8.1]2
gives a regular realization of M wrT G*=
G.
Indeed, this old
construction uses the following idea. Corresponding to T, there is a
degree n
extension L/Q(z) of Q(z)
inside the regular Galois extension L^/Q(z)
having G*
as
group. If c
is a
primitive element (generator) for it over Q(z),
then let c1,…,
cn,
be the 0th, …, n-1st powers of it,
giving a basis
of L over Q(z).
Now consider the linear form v=∑i=1n ciwi,
with
the wi's
algebraically independent of any other variable. Denote G( L^/L) by G*(1).
Elements of each
(right) coset G*(1)h, h
∈ H, produce a new linear form by
acting on the right of the ci's
(not touching the wi's).
Label the resulting n
distinct linear forms v1,…,
vn.
The matrix of
the equation – for solving for the wi's
in terms of the vi's
– is a famous invertible matrix – the discriminant
– from algebraic number theory.
Now let f(z,y)
give a regular realization of M
over Q(z). Plug in any vi
for z.
Then, the splitting fields for
all the f(vi,y)'s, over Q(w1,…,
wn),
composite to a
regular extension with group G.
The argument is almost identical to that produced in [FrJ, § 10.6]2,
famously referred to as Weil's
restriction of scalars.
The gist here – as Ax showed me in 1968 – starts with this assumption.
Suppose you have an absolutely irreducible curve C over a degree n extension K/Q. Then the
restriction of scalars
applies to the curve to give an absolutely irreducible variety W over Q which has a Q point if and only
if C has a K point. The
conclusion:
Any algebraic extension of a
P(seudo)A(lgebraically)C(losed) field is also PAC. That is, whether K
is PAC reduces to a simple test: Do absolutely irreducible curves over
the base field have K rational points. The [FrJ]2
quotation is to an unpublished manuscript of Roquette from 1975.
III. REALIZING Ker×s G* REGULARLY WHEN Ker IS ABELIAN:
Again, consider the Basic Sequence of §I, where Ker
is abelian. Reduce easily, to where Ker
is an indecomposable
(not
a direct sum of smaller G*
modules) p
group whose exponent
we take to be q.
That is, q
is the minimal integer for which q.Ker
= {0}. The first
step is to realize Ker
as a
regular extension of Q(z) without
considering the G*
action.
With no loss we can take Ker,
which is a direct sum of cyclic groups, to be Z/n.
Quotient Principle:
A regular realization of G
automatically gives a regular realization for its quotient G*.
Abelian Split Corollary: Suppose U
is a Z/n[G*]
module. Then, U is a quotient of a sum of copies of
the regular representation of G*.
In particular, U×s G*
has natural regular realizations.
Proof: As an abelian group Z/n[G*]
is a direct sum of several copies of the module M=Z/n.
Therefore, given a regular realization of M, §II
gives a regular realization of Z/n[G*]×s
G*=M wrT
G* with T
the regular representation.
Take K=Q and apply the BCL in
this simplest case. It says, if you use only n-cycles,
the minimal number of branch points you can possibly use to regularly
realize M is φ(n)=|G(Q(e2π
i/n/Q)|.
Further, to realize that case you must take the branch points as the
conjugates of a primitive generator of Q(e2π
i/n/Q).
[FrJ, Lem.~16.3.1]2 does that explicitly in what
amounts to a very old construction for the regular realization of M.
That gives us branch cycles for M, and so for the
regular reallization of Z/n[G*]t×s
G* for any value of t.
Now use that for some t there is a group cover Z/n[G*]t×s
G*→ U×s
G* to conclude from The Quotient
Principle how to construct regular realizations of U×s
G*.
Example [Dihedral
Groups]: The dihedral group case Dpk+1
is
the Basic sequence when G*=
Z/2= ± 1
and Ker
= Z/pk+1,
and p
is odd. Then, the
regular representation, Z/pk+1[G*]
is a direct sum of the trivial representation (-1 acts trivially
on Ker)
and the representation on Ker
where -1 acts by a∈Ker → -a. Similarly,
whenever the module Ker
is indecomposable, and |Ker|
is prime to |G*|,
we can be very explicit on the way the proof of the corollary
produces C'Ker.
[FrJ] M. Fried and M. Jarden, Field Arithmetic,
Springer
Ergebnisse II Vol 11
(1986) 455 pgs.,
2nd edition 2004, 780 pps.
ISBN
3-540-22811-x. We
quote here
both the
first and second ed., using [FrJ]1 and
[FrJ]2
respectively.